HI,
i wanna code for VB2008.

i wanna code to open a program in the same folder as the vb program


thanks

Process.Start("PROGRAM NAME HERE.exe")

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The above works, however for opening .exe files this is better:

Shell(Path)

Actually, Process.Start() is the better way to be doing it. The Shell() function is only there for legacy reasons.

Process and Start

I know it has been solved. Just showing my way,

Process.Start(Application.StartupPath & "\Your file.exe")

The Shell() function is a remnant of VB6; it is better practice to use Process.Start to start a program; if the file you are trying to open is not executable (ie. if it is a help manual or something else), then unfortunately you have to muddy the water by calling the Win32 API: ShellExecute still remains the only way to do this (for now): http://social.msdn.microsoft.com/for...-f2c7d32ffabc/